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jax

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  1. Hello! I don't know if this is the right place to ask this question, but still... And if this problem was already discused, sorry... I used the search button and failed to find it... I was reading Twist of the wrist 2 and I have a problem understanding something. I always like to understand how things work so that I know why a certain reaction is apropriate at a certain moment. In the third chapter of throttle control, it is writen that the rear end wants to got up under acceleration. I don't understand that. Is it meant that it wants to go up, but the torque forces off acceleration still push it down? The example which should explain this, says that we should put a bike next to a wall with the front tire facing the wall and try to accelerate. Than the rear end really goes up but ain't that becouse of the torque forces? To explain... If the bike had the center of gravity in the samo hight as the contact of the front tyre and the wall, and if the center of gravity wouldn't rise when the front forks lowered, then the rear end wouldn't rise, right? So in this case, the elevation of the rear end happens due to the forces of the wall on the bike and the torque forces... When the bike is moving, these torque forces work in the other way becouse of the acceleration. The weight distributes to the rear, right? So how can the rear end rise then? And anohter thing. A few chapters earlier it was explained that weight distribution under acceleration tends to distribute traction on the tires... It states that more gas (acceleration) transferes more weight to the rear tire... So where does the rear end tendency to elevate come in? There is an explanation that it has a tendency to rise, becouse of the direction of the rear tire spin, but if we compare that to the forces wich are a result od the weight transfer... Seems kind of irelevant PS: sorry for the crappy english... I'm not from an english talking state
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