racer Posted May 16, 2008 Report Share Posted May 16, 2008 OK... Tweek, David, et al... I lack the skill to create a good diagram. If anyone knows some place to copy/paste vector arrows and such, please let me know. Here are the numbers: Given: mass = m = 600 lbs = 272.72 kg radius = r = 50 ft = 15.38 m lean angle ( theta θ ) = 50° Find: velocity (v) = ? Formulae: gravity (g) = 9.8 m/s2 Fgrav = Fvert = m • g = 272.72 kg • 9.8 m/s2 = 2672 Newtons Fnet = Fhoriz = m • a And: circular acceleration (a) = v2/r Hence, substituting for (a): Fhoriz = m • v2/r Being that we know θ = 50° and Fvert = 2672 N, we can use our trigonometry to find Fhoriz using theta's tangent and substitute the value of Fhoriz in the equation above leaving v as the only variable to solve: TAN 50° = opposite/adjacent = Fhoriz/Fvert 1.191 = Fhoriz/2672 N Fhoriz = 1.191(2672) = 3183.2 N Substituting: Fhoriz = m • v2/r We get: 3183.2 N = 272.72 kg • v2/15.38 m v2 = (3183.2/272.72) 15.38 = 179.516 v = 13.398 m/s = 48.234 kph = 29.9 mph Thank you for your time, racer Quote Link to comment Share on other sites More sharing options...
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